If A.LIB calls routines in B.LIB, can A.LIB be built before B.LIB has been built?
The reason I'm asking this is for times when I'm not sure if A.LIB is actually calling any routines in B.LIB. If B.LIB is being called, but I don't have it, will I get unresolved externals when building A.LIB or when building the final main program that pulls everything together?